Applying The Pythagorean Theorem Homework 3

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arrobajuarez

Nov 30, 2025 · 10 min read

Applying The Pythagorean Theorem Homework 3
Applying The Pythagorean Theorem Homework 3

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    Applying the Pythagorean Theorem in Homework 3: A Comprehensive Guide

    The Pythagorean Theorem, a cornerstone of geometry, provides a fundamental relationship between the sides of a right triangle. Homework 3 often involves applying this theorem to solve various problems, ranging from simple calculations to complex, real-world scenarios. Mastering this theorem and its applications is crucial for success in mathematics and related fields.

    Understanding the Pythagorean Theorem

    At its core, the Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides (the legs). Mathematically, this is expressed as:

    a² + b² = c²

    Where:

    • a and b are the lengths of the legs of the right triangle.
    • c is the length of the hypotenuse.

    This seemingly simple equation unlocks a wealth of problem-solving possibilities, enabling us to determine unknown side lengths in right triangles, calculate distances, and even analyze geometric shapes.

    Key Concepts and Terminology

    Before diving into the applications, let's solidify our understanding of the key concepts and terminology associated with the Pythagorean Theorem:

    • Right Triangle: A triangle containing one angle that measures exactly 90 degrees. This angle is often denoted by a small square in the corner.
    • Hypotenuse: The side opposite the right angle in a right triangle. It's always the longest side of the triangle.
    • Legs: The two sides that form the right angle in a right triangle. They are also referred to as the catheti.
    • Square: The result of multiplying a number by itself. For example, the square of 5 (denoted as 5²) is 5 * 5 = 25.
    • Square Root: A value that, when multiplied by itself, equals a given number. For example, the square root of 25 (denoted as √25) is 5.

    Understanding these concepts is vital for accurately applying the Pythagorean Theorem and interpreting the results.

    Steps for Solving Pythagorean Theorem Problems

    Successfully applying the Pythagorean Theorem involves a systematic approach. Here's a step-by-step guide:

    1. Identify the Right Triangle: The first and most crucial step is to confirm that the problem involves a right triangle. Look for the presence of a 90-degree angle or any indication that the triangle is right-angled. If the triangle is not a right triangle, the Pythagorean Theorem cannot be applied.

    2. Label the Sides: Identify the hypotenuse (the side opposite the right angle) and label it as 'c'. Label the other two sides as 'a' and 'b'. It doesn't matter which leg you label 'a' and which you label 'b', as the equation is symmetrical with respect to these variables.

    3. Write the Equation: Write down the Pythagorean Theorem equation: a² + b² = c².

    4. Substitute Known Values: Substitute the known values for the sides into the equation. If you know the lengths of both legs (a and b), substitute those values. If you know the length of the hypotenuse (c) and one leg (either a or b), substitute those values accordingly.

    5. Solve for the Unknown:

      • If solving for the hypotenuse (c): Calculate a² + b², then take the square root of the result to find c.
      • If solving for a leg (a or b): Rearrange the equation to isolate the unknown leg. For example, if solving for 'a', the equation becomes: a² = c² - b². Calculate c² - b², then take the square root of the result to find a.
    6. Check Your Answer: Ensure that your answer makes sense in the context of the problem. The hypotenuse should always be the longest side of the right triangle. Also, consider the units of measurement and ensure your answer is in the correct units.

    Example Problems and Solutions

    Let's illustrate the application of the Pythagorean Theorem with several example problems commonly found in Homework 3.

    Example 1: Finding the Hypotenuse

    A right triangle has legs of length 3 cm and 4 cm. Find the length of the hypotenuse.

    1. Identify the Right Triangle: The problem states it's a right triangle.

    2. Label the Sides: a = 3 cm, b = 4 cm, c = unknown.

    3. Write the Equation: a² + b² = c²

    4. Substitute Known Values: 3² + 4² = c²

    5. Solve for the Unknown:

      • 9 + 16 = c²
      • 25 = c²
      • c = √25
      • c = 5 cm
    6. Check Your Answer: The hypotenuse is 5 cm, which is longer than both legs (3 cm and 4 cm). The answer is reasonable.

    Example 2: Finding a Leg

    A right triangle has a hypotenuse of length 13 inches and one leg of length 5 inches. Find the length of the other leg.

    1. Identify the Right Triangle: The problem states it's a right triangle.

    2. Label the Sides: c = 13 inches, a = 5 inches, b = unknown.

    3. Write the Equation: a² + b² = c²

    4. Substitute Known Values: 5² + b² = 13²

    5. Solve for the Unknown:

      • 25 + b² = 169
      • b² = 169 - 25
      • b² = 144
      • b = √144
      • b = 12 inches
    6. Check Your Answer: The leg is 12 inches, which is shorter than the hypotenuse (13 inches). The answer is reasonable.

    Example 3: Real-World Application – The Ladder Problem

    A 10-foot ladder leans against a wall. The base of the ladder is 6 feet away from the wall. How high up the wall does the ladder reach?

    1. Identify the Right Triangle: The wall, the ground, and the ladder form a right triangle. The ladder is the hypotenuse.

    2. Label the Sides: c = 10 feet (ladder), a = 6 feet (distance from the wall), b = unknown (height up the wall).

    3. Write the Equation: a² + b² = c²

    4. Substitute Known Values: 6² + b² = 10²

    5. Solve for the Unknown:

      • 36 + b² = 100
      • b² = 100 - 36
      • b² = 64
      • b = √64
      • b = 8 feet
    6. Check Your Answer: The ladder reaches 8 feet up the wall, which is less than the length of the ladder (10 feet). The answer is reasonable.

    Advanced Applications of the Pythagorean Theorem

    The Pythagorean Theorem extends beyond simple right triangle calculations. Here are some advanced applications you might encounter:

    • Distance Formula: The distance formula in coordinate geometry is derived directly from the Pythagorean Theorem. Given two points (x₁, y₁) and (x₂, y₂), the distance d between them is:

      d = √((x₂ - x₁)² + (y₂ - y₁)²)

      This formula essentially calculates the hypotenuse of a right triangle formed by the difference in x-coordinates and the difference in y-coordinates.

    • 3D Geometry: The Pythagorean Theorem can be extended to three dimensions. If you have a rectangular prism with sides of length a, b, and c, the length of the space diagonal d is:

      d = √(a² + b² + c²)

    • Trigonometry: The Pythagorean Theorem provides a foundational link to trigonometric ratios like sine, cosine, and tangent. These ratios are defined in terms of the sides of a right triangle, and their relationships are directly derived from the Pythagorean Theorem. For instance, sin(θ) = a/c, cos(θ) = b/c, and tan(θ) = a/b, where θ is one of the acute angles in the right triangle.

    • Navigation and Surveying: The Pythagorean Theorem is used in navigation and surveying to calculate distances and directions. By creating right triangles on maps or in real-world scenarios, surveyors and navigators can determine unknown distances or angles.

    • Computer Graphics: The Pythagorean Theorem is essential in computer graphics for calculating distances between points, determining lengths of lines, and performing transformations on objects.

    Common Mistakes to Avoid

    While the Pythagorean Theorem is relatively straightforward, certain common mistakes can lead to incorrect answers. Here are some pitfalls to avoid:

    • Applying the Theorem to Non-Right Triangles: The Pythagorean Theorem only applies to right triangles. Applying it to other types of triangles will result in incorrect results.

    • Incorrectly Identifying the Hypotenuse: The hypotenuse is always the side opposite the right angle. Make sure you correctly identify the hypotenuse before plugging values into the equation.

    • Algebra Errors: Errors in algebraic manipulation, such as incorrectly rearranging the equation or making mistakes when squaring or taking square roots, are common. Double-check your algebraic steps to ensure accuracy.

    • Forgetting Units: Always include the units of measurement in your final answer. Failing to include units can lead to misunderstandings and incorrect interpretations.

    • Rounding Errors: Avoid rounding intermediate calculations excessively, as this can lead to inaccuracies in the final answer. Round only at the final step, and use an appropriate number of significant figures.

    Tips for Success in Homework 3

    To excel in Homework 3 and master the applications of the Pythagorean Theorem, consider these helpful tips:

    • Practice Regularly: The key to mastering any mathematical concept is consistent practice. Work through a variety of problems to build your understanding and problem-solving skills.
    • Draw Diagrams: Visualizing the problem by drawing a diagram can often help you understand the relationships between the sides of the right triangle and identify the known and unknown values.
    • Show Your Work: Clearly show all your steps when solving problems. This will help you identify any errors you might have made and allow your instructor to understand your reasoning.
    • Check Your Answers: Always check your answers to ensure they are reasonable and make sense in the context of the problem.
    • Seek Help When Needed: Don't hesitate to ask for help from your instructor, classmates, or online resources if you're struggling with a particular concept or problem.

    Examples of Homework 3 Problems and Solutions

    Here are some example problems similar to those you might encounter in Homework 3, along with detailed solutions:

    Problem 1:

    A baseball diamond is a square with sides of 90 feet. What is the distance from home plate to second base?

    Solution:

    1. Identify the Right Triangle: The distance from home plate to first base, first base to second base, and home plate to second base form a right triangle. The distance from home plate to second base is the hypotenuse.

    2. Label the Sides: a = 90 feet, b = 90 feet, c = unknown (distance from home plate to second base).

    3. Write the Equation: a² + b² = c²

    4. Substitute Known Values: 90² + 90² = c²

    5. Solve for the Unknown:

      • 8100 + 8100 = c²
      • 16200 = c²
      • c = √16200
      • c ≈ 127.28 feet
    6. Check Your Answer: The distance from home plate to second base is approximately 127.28 feet, which is longer than the sides of the square (90 feet). The answer is reasonable.

    Problem 2:

    A ship sails 8 miles east and then 15 miles north. How far is the ship from its starting point?

    Solution:

    1. Identify the Right Triangle: The ship's eastward and northward movements form the legs of a right triangle. The distance from the starting point is the hypotenuse.

    2. Label the Sides: a = 8 miles, b = 15 miles, c = unknown (distance from the starting point).

    3. Write the Equation: a² + b² = c²

    4. Substitute Known Values: 8² + 15² = c²

    5. Solve for the Unknown:

      • 64 + 225 = c²
      • 289 = c²
      • c = √289
      • c = 17 miles
    6. Check Your Answer: The ship is 17 miles from its starting point, which is longer than both the eastward and northward distances. The answer is reasonable.

    Problem 3:

    A rectangular garden is 12 feet long and 5 feet wide. What is the length of the diagonal of the garden?

    Solution:

    1. Identify the Right Triangle: The length and width of the rectangle form the legs of a right triangle. The diagonal is the hypotenuse.

    2. Label the Sides: a = 12 feet, b = 5 feet, c = unknown (length of the diagonal).

    3. Write the Equation: a² + b² = c²

    4. Substitute Known Values: 12² + 5² = c²

    5. Solve for the Unknown:

      • 144 + 25 = c²
      • 169 = c²
      • c = √169
      • c = 13 feet
    6. Check Your Answer: The diagonal is 13 feet, which is longer than both the length and width of the garden. The answer is reasonable.

    Conclusion

    The Pythagorean Theorem is a fundamental concept in mathematics with wide-ranging applications. Mastering this theorem and its applications is essential for success in geometry, trigonometry, and related fields. By understanding the underlying principles, following a systematic approach to problem-solving, and practicing regularly, you can confidently tackle any Pythagorean Theorem problem you encounter in Homework 3 and beyond. Remember to draw diagrams, show your work, check your answers, and seek help when needed. With dedication and perseverance, you can unlock the power of the Pythagorean Theorem and excel in your mathematical studies. Good luck!

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