Divide The Compounds Below Into Meso Or Non-meso Compounds.

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arrobajuarez

Nov 21, 2025 · 10 min read

Divide The Compounds Below Into Meso Or Non-meso Compounds.
Divide The Compounds Below Into Meso Or Non-meso Compounds.

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    Classifying compounds as meso or non-meso requires understanding their structure and symmetry. Meso compounds, while possessing chiral centers, are achiral due to an internal plane of symmetry. This internal symmetry cancels out the optical activity that would normally arise from chiral centers. Non-meso compounds, on the other hand, lack this internal plane of symmetry and are typically chiral, thus optically active.

    To determine whether a compound is meso or non-meso, you need to examine its molecular structure, identify any chiral centers, and then look for an internal plane of symmetry. If a compound has chiral centers but also has a plane of symmetry, it is a meso compound. If it has chiral centers and lacks a plane of symmetry, it is a non-meso compound. If it lacks chiral centers altogether, it is neither meso nor chiral.

    Let's delve into a detailed explanation of meso and non-meso compounds, and then apply this knowledge to classify several example compounds.

    Understanding Meso Compounds

    A meso compound is a molecule with multiple chiral centers but is achiral due to the presence of an internal plane of symmetry. This plane of symmetry divides the molecule into two halves that are mirror images of each other. Because of this symmetry, the stereochemical configurations of the chiral centers cancel each other out, resulting in no net optical rotation.

    Key characteristics of meso compounds:

    • Chiral Centers: Meso compounds must have at least two chiral centers. A chiral center is an atom (usually carbon) bonded to four different groups.
    • Plane of Symmetry: The molecule must possess an internal plane of symmetry. This plane cuts through the molecule in such a way that one half of the molecule is a mirror image of the other half.
    • Achiral: Despite having chiral centers, meso compounds are achiral and do not rotate plane-polarized light.
    • Superimposable Mirror Images: Meso compounds are superimposable on their mirror images, which is a characteristic of achiral molecules.

    Understanding Non-Meso Compounds

    A non-meso compound, in contrast, is a molecule that either lacks chiral centers or has chiral centers but lacks an internal plane of symmetry. These compounds are typically chiral and optically active, meaning they can rotate plane-polarized light.

    Key characteristics of non-meso compounds:

    • May or May Not Have Chiral Centers: Non-meso compounds can either have no chiral centers or possess one or more.
    • No Plane of Symmetry: If chiral centers are present, the molecule must lack an internal plane of symmetry.
    • Chiral (Typically): Most non-meso compounds are chiral and optically active.
    • Non-Superimposable Mirror Images: Chiral non-meso compounds have non-superimposable mirror images, known as enantiomers.

    Steps to Classify Compounds as Meso or Non-Meso

    To effectively classify compounds as meso or non-meso, follow these steps:

    1. Identify Chiral Centers: Look for carbon atoms bonded to four different groups. Mark these as chiral centers.
    2. Draw the Structure Clearly: Ensure the structure is drawn in a way that clearly shows the spatial arrangement of atoms and groups. Use wedges and dashes to indicate stereochemistry.
    3. Look for a Plane of Symmetry: Examine the molecule for an internal plane of symmetry. Visualize whether cutting the molecule in half would result in two mirror-image halves.
    4. Determine Meso or Non-Meso:
      • If chiral centers are present and a plane of symmetry exists, the compound is meso.
      • If no chiral centers are present, the compound is neither meso nor chiral.
      • If chiral centers are present and there is no plane of symmetry, the compound is non-meso.
    5. Confirm Chirality (for Non-Meso): For non-meso compounds, confirm that the molecule and its mirror image are non-superimposable. This confirms its chirality.

    Examples and Classifications

    Let's apply these principles to classify several compounds. We'll examine each compound, identify chiral centers, look for planes of symmetry, and then classify them as meso or non-meso.

    Example 1: 2,3-Dichlorobutane

    Structure: CH3-CHCl-CHCl-CH3

    1. Identify Chiral Centers: Carbons 2 and 3 are chiral centers because each is bonded to four different groups: H, Cl, CH3, and the adjacent carbon.
    2. Draw the Structure Clearly: We need to consider different stereoisomers: (2R,3R), (2S,3S), and (2R,3S) (which is the same as (2S,3R)).
    3. Look for a Plane of Symmetry:
      • (2R,3R) and (2S,3S): These enantiomers do not have a plane of symmetry.
      • (2R,3S): This isomer has a plane of symmetry that cuts through the middle of the C2-C3 bond.
    4. Determine Meso or Non-Meso:
      • (2R,3R) and (2S,3S): Non-meso (chiral)
      • (2R,3S): Meso (achiral)

    Conclusion: 2,3-Dichlorobutane can exist as both meso and non-meso compounds, depending on the stereochemistry.

    Example 2: 2,4-Dichloropentane

    Structure: CH3-CHCl-CH2-CHCl-CH3

    1. Identify Chiral Centers: Carbons 2 and 4 are chiral centers.
    2. Draw the Structure Clearly: Consider the stereoisomers: (2R,4R), (2S,4S), and (2R,4S) (which is the same as (2S,4R)).
    3. Look for a Plane of Symmetry:
      • (2R,4R) and (2S,4S): These enantiomers do not have a plane of symmetry.
      • (2R,4S): This isomer has a plane of symmetry passing through the central CH2 group.
    4. Determine Meso or Non-Meso:
      • (2R,4R) and (2S,4S): Non-meso (chiral)
      • (2R,4S): Meso (achiral)

    Conclusion: Similar to 2,3-dichlorobutane, 2,4-dichloropentane can also be meso or non-meso depending on the stereochemistry.

    Example 3: 1,2-Cyclohexanediol

    Structure: A cyclohexane ring with -OH groups on carbons 1 and 2.

    1. Identify Chiral Centers: Carbons 1 and 2 are chiral centers if the -OH groups are on the same side of the ring (cis). If the -OH groups are on opposite sides (trans), the molecule has different properties.
    2. Draw the Structure Clearly: Draw both the cis and trans isomers.
    3. Look for a Plane of Symmetry:
      • cis-1,2-Cyclohexanediol: Has a plane of symmetry bisecting the molecule between carbons 1 and 2.
      • trans-1,2-Cyclohexanediol: Does not have a plane of symmetry.
    4. Determine Meso or Non-Meso:
      • cis-1,2-Cyclohexanediol: Meso (achiral)
      • trans-1,2-Cyclohexanediol: Non-meso (chiral)

    Conclusion: cis-1,2-Cyclohexanediol is a meso compound, while trans-1,2-Cyclohexanediol is a non-meso compound.

    Example 4: 2-Chlorobutane

    Structure: CH3-CHCl-CH2-CH3

    1. Identify Chiral Centers: Carbon 2 is a chiral center.
    2. Draw the Structure Clearly: Draw the structure.
    3. Look for a Plane of Symmetry: The molecule does not have a plane of symmetry.
    4. Determine Meso or Non-Meso: Non-meso (chiral)

    Conclusion: 2-Chlorobutane is a non-meso compound because it has a chiral center but no plane of symmetry.

    Example 5: Tartaric Acid (2,3-Dihydroxybutanedioic Acid)

    Structure: HOOC-CH(OH)-CH(OH)-COOH

    1. Identify Chiral Centers: Carbons 2 and 3 are chiral centers.
    2. Draw the Structure Clearly: Consider the stereoisomers: (2R,3R), (2S,3S), and (2R,3S).
    3. Look for a Plane of Symmetry:
      • (2R,3R) and (2S,3S): These enantiomers do not have a plane of symmetry.
      • (2R,3S): This isomer has a plane of symmetry.
    4. Determine Meso or Non-Meso:
      • (2R,3R) and (2S,3S): Non-meso (chiral)
      • (2R,3S): Meso (achiral)

    Conclusion: Tartaric acid can exist as both meso and non-meso compounds. The (2R,3S) isomer is the meso form.

    Example 6: Glyceraldehyde

    Structure: HOCH2-CH(OH)-CHO

    1. Identify Chiral Centers: Carbon 2 is a chiral center.
    2. Draw the Structure Clearly: Draw the structure.
    3. Look for a Plane of Symmetry: The molecule does not have a plane of symmetry.
    4. Determine Meso or Non-Meso: Non-meso (chiral)

    Conclusion: Glyceraldehyde is a non-meso compound.

    Example 7: 1,4-Dichlorocyclohexane

    Structure: A cyclohexane ring with chlorine atoms on carbons 1 and 4.

    1. Identify Chiral Centers: Carbons 1 and 4 could be considered pseudo-chiral centers depending on whether the chlorines are cis or trans.
    2. Draw the Structure Clearly: Draw both cis and trans isomers.
    3. Look for a Plane of Symmetry:
      • cis-1,4-Dichlorocyclohexane: Has a plane of symmetry passing through carbons 1 and 4.
      • trans-1,4-Dichlorocyclohexane: Has a plane of symmetry perpendicular to the ring.
    4. Determine Meso or Non-Meso:
      • cis-1,4-Dichlorocyclohexane: Meso (achiral)
      • trans-1,4-Dichlorocyclohexane: Meso (achiral)

    Conclusion: Both cis and trans isomers of 1,4-dichlorocyclohexane are meso compounds.

    Example 8: 2,3-Dibromopentane

    Structure: CH3-CHBr-CHBr-CH2-CH3

    1. Identify Chiral Centers: Carbons 2 and 3 are chiral centers.
    2. Draw the Structure Clearly: Draw the structure considering stereochemistry.
    3. Look for a Plane of Symmetry:
      • (2R,3R) and (2S,3S): These enantiomers do not have a plane of symmetry.
      • (2R,3S): This isomer has no plane of symmetry.
    4. Determine Meso or Non-Meso:
      • (2R,3R), (2S,3S), and (2R,3S): Non-meso (chiral)

    Conclusion: 2,3-Dibromopentane exists only as non-meso compounds.

    Example 9: Cyclopentane-1,2-dicarboxylic acid

    Structure: A cyclopentane ring with carboxylic acid groups on carbons 1 and 2.

    1. Identify Chiral Centers: Carbons 1 and 2 are chiral centers (if cis).
    2. Draw the Structure Clearly: Draw both cis and trans isomers.
    3. Look for a Plane of Symmetry:
      • cis-Cyclopentane-1,2-dicarboxylic acid: Has a plane of symmetry.
      • trans-Cyclopentane-1,2-dicarboxylic acid: No plane of symmetry.
    4. Determine Meso or Non-Meso:
      • cis-Cyclopentane-1,2-dicarboxylic acid: Meso
      • trans-Cyclopentane-1,2-dicarboxylic acid: Non-meso

    Conclusion: The cis isomer is a meso compound, while the trans isomer is a non-meso compound.

    Example 10: 1,3-Dichlorocyclopentane

    Structure: Cyclopentane ring with chlorine atoms on carbons 1 and 3.

    1. Identify Chiral Centers: Carbons 1 and 3 could be chiral depending on whether they are cis or trans.
    2. Draw the Structure Clearly: Draw both cis and trans isomers.
    3. Look for a Plane of Symmetry:
      • cis-1,3-Dichlorocyclopentane: Has a plane of symmetry passing through carbon 2.
      • trans-1,3-Dichlorocyclopentane: No plane of symmetry.
    4. Determine Meso or Non-Meso:
      • cis-1,3-Dichlorocyclopentane: Meso
      • trans-1,3-Dichlorocyclopentane: Non-meso

    Conclusion: The cis isomer is a meso compound, while the trans isomer is a non-meso compound.

    Common Pitfalls

    • Confusing Chirality and Chiral Centers: Just because a molecule has chiral centers doesn't automatically make it chiral. Meso compounds have chiral centers but are achiral due to symmetry.
    • Incorrectly Identifying Planes of Symmetry: Ensure the plane truly divides the molecule into two identical halves. Sometimes the symmetry is not immediately obvious.
    • Ignoring Stereochemistry: Always consider the stereochemistry of the chiral centers. Different stereoisomers can lead to different classifications (meso vs. non-meso).
    • Assuming All Cyclic Compounds with Substituents are Chiral: Cyclic compounds can have planes of symmetry, making them meso, as seen in several examples above.

    Importance of Understanding Meso Compounds

    The concept of meso compounds is crucial in organic chemistry for several reasons:

    • Stereochemistry: Understanding meso compounds is fundamental to understanding stereochemistry, which is essential for predicting and explaining the properties of molecules.
    • Reaction Outcomes: The presence of a meso compound as a reactant or product can significantly affect the outcome of a chemical reaction, particularly in stereospecific reactions.
    • Drug Design: In the pharmaceutical industry, the stereochemistry of a drug molecule can drastically affect its biological activity. Recognizing and designing around meso compounds can be crucial.
    • Spectroscopy: Meso compounds have unique spectroscopic properties (e.g., NMR, IR) due to their symmetry, which can aid in their identification.

    Conclusion

    Classifying compounds as meso or non-meso involves careful consideration of their structure, stereochemistry, and symmetry. By following a systematic approach—identifying chiral centers, drawing structures clearly, looking for planes of symmetry, and confirming chirality—you can accurately classify a wide variety of organic compounds. Remember that meso compounds possess chiral centers but are achiral due to an internal plane of symmetry, while non-meso compounds lack this symmetry and are typically chiral. A solid understanding of these concepts is vital for success in organic chemistry and related fields.

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