Find The Interval Of Convergence Of The Power Series Chegg

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arrobajuarez

Oct 28, 2025 · 8 min read

Find The Interval Of Convergence Of The Power Series Chegg
Find The Interval Of Convergence Of The Power Series Chegg

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    Navigating the complexities of power series convergence can feel like traversing a mathematical maze. But with a methodical approach, understanding the interval of convergence becomes achievable. This article will guide you through the process, offering clear explanations and practical steps, even if you're tackling a problem found on Chegg.

    Understanding Power Series and Convergence

    A power series is an infinite series of the form:

    ∑ cₙ(x - a)ⁿ

    Where:

    • x is a variable.
    • cₙ are coefficients.
    • a is the center of the series.

    The critical question is: For what values of x does this series converge? The set of all such x values is known as the interval of convergence. Determining this interval is crucial for understanding where the power series is a valid representation of a function. The interval is typically found using the Ratio Test or the Root Test. These tests provide a radius of convergence, and further analysis is needed to determine if the endpoints of the interval are included.

    Key Concepts and Definitions

    Before diving into the process, let's solidify some core concepts:

    • Radius of Convergence (R): A non-negative real number or ∞ that represents how far from the center a the power series converges.

    • Interval of Convergence: The interval (or set) of x values for which the power series converges. It's typically of the form (a - R, a + R), [a - R, a + R), (a - R, a + R], or [a - R, a + R], where the brackets indicate inclusion of the endpoint.

    • Ratio Test: A test used to determine the convergence of a series by examining the limit of the ratio of consecutive terms:

      L = lim (n→∞) |aₙ₊₁ / aₙ|

      • If L < 1, the series converges absolutely.
      • If L > 1, the series diverges.
      • If L = 1, the test is inconclusive.
    • Root Test: Another test for convergence, using the nth root of the absolute value of the terms:

      L = lim (n→∞) |aₙ|^(1/n)

      • If L < 1, the series converges absolutely.
      • If L > 1, the series diverges.
      • If L = 1, the test is inconclusive.

    Step-by-Step Guide to Finding the Interval of Convergence

    Here's a structured approach to finding the interval of convergence for a given power series:

    1. Identify the Power Series Components:

    • Determine the coefficients cₙ and the center a. This often involves careful observation of the series' form.

    2. Apply the Ratio or Root Test:

    • Ratio Test: Calculate the limit:
      L = lim (n→∞) |cₙ₊₁(x - a)ⁿ⁺¹ / cₙ(x - a)ⁿ| = lim (n→∞) |(cₙ₊₁ / cₙ)(x - a)| = |x - a| lim (n→∞) |cₙ₊₁ / cₙ|
    
    • Root Test: Calculate the limit:
      L = lim (n→∞) |cₙ(x - a)ⁿ|^(1/n) = lim (n→∞) |cₙ|^(1/n) |x - a| = |x - a| lim (n→∞) |cₙ|^(1/n)
    
    • Choose the test that seems most appropriate for the given series. The Ratio Test is often easier to apply when the coefficients involve factorials or exponential terms. The Root Test is useful when the entire term aₙ is raised to the power of n.

    3. Solve for the Radius of Convergence (R):

    • For convergence, we need L < 1. Therefore:
      |x - a| lim (n→∞) |cₙ₊₁ / cₙ| < 1  (Ratio Test)
    
      |x - a| lim (n→∞) |cₙ|^(1/n) < 1  (Root Test)
    
    • Isolate |x - a|:
      |x - a| < 1 / lim (n→∞) |cₙ₊₁ / cₙ| = R  (Ratio Test)
    
      |x - a| < 1 / lim (n→∞) |cₙ|^(1/n) = R  (Root Test)
    
    • The radius of convergence is:
      R = 1 / lim (n→∞) |cₙ₊₁ / cₙ|  (Ratio Test)
    
      R = 1 / lim (n→∞) |cₙ|^(1/n)  (Root Test)
    
    • If the limit is 0, then R = ∞ (the series converges for all x). If the limit is ∞, then R = 0 (the series converges only at x = a).

    4. Determine the Potential Interval of Convergence:

    • The inequality |x - a| < R translates to:
      -R < x - a < R
    
      a - R < x < a + R
    
    • This gives us the potential interval of convergence: (a - R, a + R). This interval excludes the endpoints.

    5. Test the Endpoints:

    • The most crucial step! You must test the endpoints x = a - R and x = a + R separately by plugging them back into the original power series.

    • At x = a - R: Substitute x = a - R into the original power series and evaluate the resulting series. Determine if it converges (using tests like the Alternating Series Test, Comparison Test, Limit Comparison Test, or Integral Test).

    • At x = a + R: Substitute x = a + R into the original power series and evaluate the resulting series. Determine if it converges.

    6. Write the Final Interval of Convergence:

    • Based on the endpoint testing:
      *   If both endpoints converge, the interval is [a - R, a + R].
      *   If *a - R* converges and *a + R* diverges, the interval is [a - R, a + R).
      *   If *a - R* diverges and *a + R* converges, the interval is (a - R, a + R].
      *   If both endpoints diverge, the interval is (a - R, a + R).
    

    Examples

    Let's illustrate this process with a couple of examples:

    Example 1:

    Find the interval of convergence of the power series:

    ∑ (x - 2)ⁿ / n

    1. Identify Components:

    • cₙ = 1/n
    • a = 2

    2. Apply the Ratio Test:

    L = lim (n→∞) |((x - 2)ⁿ⁺¹ / (n+1)) / ((x - 2)ⁿ / n)| = lim (n→∞) |(x - 2) * (n / (n+1))| = |x - 2| lim (n→∞) |n / (n+1)| = |x - 2| * 1 = |x - 2|

    3. Solve for R:

    |x - 2| < 1 => R = 1

    4. Potential Interval:

    2 - 1 < x < 2 + 1 => 1 < x < 3 => (1, 3)

    5. Test Endpoints:

    • x = 1: ∑ (1 - 2)ⁿ / n = ∑ (-1)ⁿ / n. This is an alternating series. Since 1/n is decreasing and approaches 0, the Alternating Series Test tells us this converges.
    • x = 3: ∑ (3 - 2)ⁿ / n = ∑ 1/n. This is the harmonic series, which is known to diverge.

    6. Final Interval:

    Since x = 1 converges and x = 3 diverges, the interval of convergence is [1, 3).

    Example 2:

    Find the interval of convergence of the power series:

    ∑ ((-1)ⁿ * x²ⁿ) / (4ⁿ * (n!)²)

    1. Identify Components:

    • cₙ = ((-1)ⁿ) / (4ⁿ * (n!)²)
    • a = 0

    2. Apply the Ratio Test:

    L = lim (n→∞) |(((-1)ⁿ⁺¹ * x²⁽ⁿ⁺¹⁾) / (4ⁿ⁺¹ * ((n+1)!)²)) / (((-1)ⁿ * x²ⁿ) / (4ⁿ * (n!)²))|

    = lim (n→∞) |(x² / 4) * ((n!)² / ((n+1)!)²)|

    = lim (n→∞) |(x² / 4) * (1 / (n+1)²)|

    = |x² / 4| * lim (n→∞) |1 / (n+1)²| = |x² / 4| * 0 = 0

    3. Solve for R:

    Since L = 0 < 1 for all x, the radius of convergence R = ∞.

    4. Potential Interval:

    (-∞, ∞)

    5. Test Endpoints:

    Since the interval is (-∞, ∞), there are no endpoints to test.

    6. Final Interval:

    The interval of convergence is (-∞, ∞). The series converges for all real numbers x.

    Common Mistakes to Avoid

    • Forgetting to Test Endpoints: This is the most common error. Always, always, always test the endpoints separately!
    • Incorrectly Applying the Ratio or Root Test: Double-check your algebraic manipulations and limit calculations.
    • Misidentifying the Center (a): Pay close attention to the form (x - a)ⁿ.
    • Confusing Convergence Tests: Make sure you're using the appropriate test for the resulting series after substituting the endpoints.
    • Assuming R = ∞ means Divergence: R = ∞ means the series converges for all x.
    • Algebra Errors: Be meticulous with your algebra, especially when dealing with factorials.

    Advanced Techniques and Considerations

    • Term-by-Term Differentiation and Integration: Power series can be differentiated and integrated term-by-term within their interval of convergence. This is a powerful technique for finding power series representations of related functions.
    • Analytic Functions: Functions that can be represented by a power series are called analytic functions. They have infinitely many derivatives and are "smooth" within their interval of convergence.
    • Complex Power Series: The concept of the interval of convergence extends to complex numbers, where it becomes a disk of convergence in the complex plane.
    • Laurent Series: A generalization of power series that allows for negative powers of (x - a). Laurent series are used to represent functions with singularities.
    • Using Known Series: Sometimes, you can manipulate a given series to resemble a known series (like the geometric series, the exponential series, or the Taylor series for sine or cosine). This can simplify the process of finding the interval of convergence.

    The Chegg Connection and Academic Integrity

    Chegg can be a valuable resource for understanding mathematical concepts and problem-solving techniques. However, it's crucial to use it responsibly and ethically:

    • Don't Simply Copy Answers: The goal is to learn, not just get the right answer. Understand the steps involved in solving the problem.
    • Use Chegg as a Study Aid: Work through problems yourself first, and then use Chegg to check your work or get hints if you're stuck.
    • Focus on Understanding the Concepts: Pay attention to the explanations and reasoning behind the solutions.
    • Cite Your Sources: If you use information from Chegg in your own work, be sure to cite it properly to avoid plagiarism.
    • Be Aware of Your University's Academic Honesty Policy: Understand the rules regarding the use of online resources.

    Finding the interval of convergence requires a solid understanding of power series, convergence tests, and careful attention to detail. While resources like Chegg can provide assistance, the ultimate goal is to develop your own problem-solving skills and conceptual understanding. By following the steps outlined in this article, practicing with examples, and avoiding common mistakes, you can master the art of determining the interval of convergence for any power series you encounter. Remember that mathematics is a journey of discovery, and each problem solved brings you one step closer to a deeper understanding of the subject.

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