For Each Positive Integer K Let Ak
arrobajuarez
Nov 26, 2025 · 13 min read
Table of Contents
Let's dive into the fascinating world of sequences and their properties, specifically focusing on a sequence defined by the recursive formula a<sub>k</sub>. Understanding such sequences requires a blend of algebraic manipulation, pattern recognition, and sometimes a bit of number theory. Our objective is to comprehensively analyze the sequence defined by "for each positive integer k, let a<sub>k</sub>." This means we will explore the definition, potential closed-form expressions, and some interesting properties this sequence might possess. Since the prompt is incomplete, we will consider several possible interpretations and analyze each one. We will begin with the simplest case, slowly increasing the complexity to better understand the diverse ways in which sequence definitions can manifest.
Interpretation 1: A Simple Arithmetic Sequence
Let's assume the simplest possible interpretation: a<sub>k</sub> = k for each positive integer k.
Definition
This defines a very basic arithmetic sequence. The first term a<sub>1</sub> = 1, the second term a<sub>2</sub> = 2, and so on. Each term is simply equal to its index.
Closed-Form Expression
The closed-form expression is trivially a<sub>k</sub> = k. This means we can directly calculate any term of the sequence by simply substituting the desired index k.
Properties
-
Arithmetic Progression: This is an arithmetic progression with a common difference of 1.
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Monotonically Increasing: The sequence is strictly increasing as each term is larger than the previous one.
-
Sum of First n Terms: The sum of the first n terms of this sequence is given by the well-known formula:
∑<sub>k=1</sub><sup>n</sup> a<sub>k</sub> = ∑<sub>k=1</sub><sup>n</sup> k = n( n + 1) / 2
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No Upper Bound: The sequence tends to infinity as k increases.
Example
- a<sub>1</sub> = 1
- a<sub>5</sub> = 5
- a<sub>100</sub> = 100
Interpretation 2: A Linear Sequence
Let's now consider a slightly more complex, but still linear, interpretation: a<sub>k</sub> = ak for some constant 'a'. This is slightly ambiguous, but the most logical assumption is that 'a' is a real number.
Definition
This defines a linear sequence where each term is a constant multiple of its index.
Closed-Form Expression
The closed-form expression is simply a<sub>k</sub> = ak.
Properties
-
Arithmetic Progression: This is an arithmetic progression with a common difference of 'a'.
-
Monotonicity: The sequence is monotonically increasing if a > 0, monotonically decreasing if a < 0, and constant if a = 0.
-
Sum of First n Terms: The sum of the first n terms is:
∑<sub>k=1</sub><sup>n</sup> a<sub>k</sub> = ∑<sub>k=1</sub><sup>n</sup> ak = a ∑<sub>k=1</sub><sup>n</sup> k = a n( n + 1) / 2
Example
- If a = 2, then a<sub>1</sub> = 2, a<sub>5</sub> = 10, a<sub>100</sub> = 200.
- If a = -1, then a<sub>1</sub> = -1, a<sub>5</sub> = -5, a<sub>100</sub> = -100.
Interpretation 3: A Recurrence Relation
Let's consider a recurrence relation where a<sub>k</sub> depends on the previous terms: a<sub>k</sub> = a<sub>k-1</sub> + k. We will need an initial condition, so let's assume a<sub>1</sub> = 1.
Definition
This defines a sequence where each term is the sum of the previous term and the current index.
Finding a Closed-Form Expression
- a<sub>1</sub> = 1
- a<sub>2</sub> = a<sub>1</sub> + 2 = 1 + 2 = 3
- a<sub>3</sub> = a<sub>2</sub> + 3 = 3 + 3 = 6
- a<sub>4</sub> = a<sub>3</sub> + 4 = 6 + 4 = 10
- a<sub>5</sub> = a<sub>4</sub> + 5 = 10 + 5 = 15
Observing the first few terms, we see that a<sub>k</sub> appears to be the sum of the first k integers. Therefore, we can hypothesize that a<sub>k</sub> = k( k + 1) / 2.
We can prove this by induction:
-
Base Case: For k = 1, a<sub>1</sub> = 1*(1+1)/2 = 1, which is true.
-
Inductive Hypothesis: Assume a<sub>n</sub> = n( n + 1) / 2 for some integer n ≥ 1.
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Inductive Step: We need to show that a<sub>n+1</sub> = (n+1)(n+2) / 2.
a<sub>n+1</sub> = a<sub>n</sub> + (n + 1) (by the recurrence relation) a<sub>n+1</sub> = n( n + 1) / 2 + (n + 1) (by the inductive hypothesis) a<sub>n+1</sub> = [n( n + 1) + 2(n + 1)] / 2 a<sub>n+1</sub> = (n + 1)(n + 2) / 2
Therefore, the closed-form expression is a<sub>k</sub> = k( k + 1) / 2.
Properties
-
Quadratic Sequence: This is a quadratic sequence.
-
Monotonically Increasing: The sequence is strictly increasing.
-
Sum of First n Terms: The sum of the first n terms is:
∑<sub>k=1</sub><sup>n</sup> a<sub>k</sub> = ∑<sub>k=1</sub><sup>n</sup> k( k + 1) / 2 = (1/2) ∑<sub>k=1</sub><sup>n</sup> (k<sup>2</sup> + k) = (1/2) [ n( n + 1)(2n + 1) / 6 + n( n + 1) / 2 ] = n( n + 1)(n + 2) / 6
-
Relation to Triangular Numbers: a<sub>k</sub> is the k-th triangular number.
Example
- a<sub>1</sub> = 1
- a<sub>5</sub> = 5 * 6 / 2 = 15
- a<sub>10</sub> = 10 * 11 / 2 = 55
Interpretation 4: A More Complex Recurrence
Let's consider a recurrence relation a<sub>k</sub> = k a<sub>k-1</sub>. Again, we need an initial condition, so let a<sub>1</sub> = 1.
Definition
This defines a sequence where each term is the product of the previous term and the current index.
Finding a Closed-Form Expression
- a<sub>1</sub> = 1
- a<sub>2</sub> = 2 * a<sub>1</sub> = 2 * 1 = 2
- a<sub>3</sub> = 3 * a<sub>2</sub> = 3 * 2 = 6
- a<sub>4</sub> = 4 * a<sub>3</sub> = 4 * 6 = 24
- a<sub>5</sub> = 5 * a<sub>4</sub> = 5 * 24 = 120
Observing the first few terms, we recognize that a<sub>k</sub> = k! (k factorial).
We can prove this by induction:
-
Base Case: For k = 1, a<sub>1</sub> = 1 = 1!, which is true.
-
Inductive Hypothesis: Assume a<sub>n</sub> = n! for some integer n ≥ 1.
-
Inductive Step: We need to show that a<sub>n+1</sub> = (n+1)!.
a<sub>n+1</sub> = (n + 1) * a<sub>n</sub> (by the recurrence relation) a<sub>n+1</sub> = (n + 1) * n! (by the inductive hypothesis) a<sub>n+1</sub> = (n + 1)!
Therefore, the closed-form expression is a<sub>k</sub> = k!.
Properties
- Factorial Sequence: This is the factorial sequence.
- Rapidly Increasing: The sequence increases very rapidly.
- Relation to Permutations: a<sub>k</sub> represents the number of permutations of k distinct objects.
Example
- a<sub>1</sub> = 1
- a<sub>5</sub> = 5! = 120
- a<sub>10</sub> = 10! = 3,628,800
Interpretation 5: A Trigonometric Sequence
Let’s explore a trigonometric possibility: a<sub>k</sub> = sin(k). We'll assume the argument of the sine function is in radians.
Definition
This defines a sequence where each term is the sine of the index k.
Closed-Form Expression
The closed-form expression is a<sub>k</sub> = sin(k).
Properties
-
Bounded: The sequence is bounded between -1 and 1, i.e., -1 ≤ a<sub>k</sub> ≤ 1.
-
Non-Monotonic: The sequence is non-monotonic; it oscillates between positive and negative values.
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Periodic-like Behavior: While not strictly periodic (since π is irrational), the sequence exhibits periodic-like behavior.
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No Simple Sum Formula: There isn’t a simple closed-form expression for the sum of the first n terms of this sequence. It requires more advanced techniques or numerical approximation.
Example
- a<sub>1</sub> = sin(1) ≈ 0.841
- a<sub>5</sub> = sin(5) ≈ -0.959
- a<sub>10</sub> = sin(10) ≈ -0.544
Interpretation 6: An Exponential Sequence
Let’s consider a<sub>k</sub> = k<sup>k</sup>.
Definition
This defines a sequence where each term is the index k raised to the power of k.
Closed-Form Expression
The closed-form expression is a<sub>k</sub> = k<sup>k</sup>.
Properties
-
Rapidly Increasing: This sequence increases very rapidly, even faster than the factorial sequence.
-
No Simple Sum Formula: There isn’t a simple closed-form expression for the sum of the first n terms of this sequence.
Example
- a<sub>1</sub> = 1<sup>1</sup> = 1
- a<sub>2</sub> = 2<sup>2</sup> = 4
- a<sub>3</sub> = 3<sup>3</sup> = 27
- a<sub>4</sub> = 4<sup>4</sup> = 256
- a<sub>5</sub> = 5<sup>5</sup> = 3125
Interpretation 7: A Sequence of Prime Numbers
Let a<sub>k</sub> be the k-th prime number.
Definition
This defines a sequence where the k-th term is the k-th prime number.
Closed-Form Expression
There is no known simple closed-form expression for a<sub>k</sub>, the k-th prime number. There are approximations, but no exact formula.
Properties
-
Infinitely Many Terms: The sequence is infinite because there are infinitely many prime numbers.
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Irregular Distribution: The distribution of prime numbers is irregular, and finding large prime numbers is a major research area in number theory.
-
Monotonically Increasing: The sequence is strictly increasing.
Example
- a<sub>1</sub> = 2 (the first prime number)
- a<sub>2</sub> = 3 (the second prime number)
- a<sub>3</sub> = 5 (the third prime number)
- a<sub>4</sub> = 7 (the fourth prime number)
- a<sub>5</sub> = 11 (the fifth prime number)
Interpretation 8: A Combination Sequence
Let’s define a more complex recurrence: a<sub>k</sub> = a<sub>k-1</sub> + k<sup>2</sup> with a<sub>1</sub> = 1.
Definition
Each term is the sum of the previous term and the square of the current index.
Finding a Closed-Form Expression
- a<sub>1</sub> = 1
- a<sub>2</sub> = a<sub>1</sub> + 2<sup>2</sup> = 1 + 4 = 5
- a<sub>3</sub> = a<sub>2</sub> + 3<sup>2</sup> = 5 + 9 = 14
- a<sub>4</sub> = a<sub>3</sub> + 4<sup>2</sup> = 14 + 16 = 30
- a<sub>5</sub> = a<sub>4</sub> + 5<sup>2</sup> = 30 + 25 = 55
This sequence represents the sum of the squares of the first k integers, plus 0. Therefore:
a<sub>k</sub> = ∑<sub>i=1</sub><sup>k</sup> i<sup>2</sup> = k( k + 1)(2k + 1) / 6
We can prove this by induction:
-
Base Case: For k = 1, a<sub>1</sub> = 1*(1+1)(2*1+1)/6 = 1, which is true.
-
Inductive Hypothesis: Assume a<sub>n</sub> = n( n + 1)(2n + 1) / 6 for some integer n ≥ 1.
-
Inductive Step: We need to show that a<sub>n+1</sub> = (n+1)(n+2)(2(n+1) + 1) / 6 = (n+1)(n+2)(2n+3) / 6.
a<sub>n+1</sub> = a<sub>n</sub> + (n + 1)<sup>2</sup> (by the recurrence relation) a<sub>n+1</sub> = n( n + 1)(2n + 1) / 6 + (n + 1)<sup>2</sup> (by the inductive hypothesis) a<sub>n+1</sub> = [ n( n + 1)(2n + 1) + 6(n + 1)<sup>2</sup> ] / 6 a<sub>n+1</sub> = (n + 1)[ n(2n + 1) + 6(n + 1) ] / 6 a<sub>n+1</sub> = (n + 1)[ 2n<sup>2</sup> + n + 6n + 6 ] / 6 a<sub>n+1</sub> = (n + 1)[ 2n<sup>2</sup> + 7n + 6 ] / 6 a<sub>n+1</sub> = (n + 1)(n + 2)(2n + 3) / 6
Therefore, the closed-form expression is a<sub>k</sub> = k( k + 1)(2k + 1) / 6.
Properties
- Cubic Sequence: This is a cubic sequence.
- Monotonically Increasing: The sequence is strictly increasing.
- Sum of Squares: a<sub>k</sub> is the sum of the first k perfect squares.
Example
- a<sub>1</sub> = 1
- a<sub>5</sub> = 5 * 6 * 11 / 6 = 55
- a<sub>10</sub> = 10 * 11 * 21 / 6 = 385
Interpretation 9: Piecewise Function
Let’s define a<sub>k</sub> as a piecewise function:
- a<sub>k</sub> = k, if k is even
- a<sub>k</sub> = k<sup>2</sup>, if k is odd
Definition
This defines a sequence that alternates between the index and the square of the index, depending on whether the index is even or odd.
Closed-Form Expression
While there isn't a single simple expression, we can express this using the modulo operator:
a<sub>k</sub> = k, if k mod 2 = 0 a<sub>k</sub> = k<sup>2</sup>, if k mod 2 = 1
Properties
- Non-Monotonic (Generally): While the sequence tends to increase, it is not strictly monotonic. For example, a<sub>2</sub> = 2, and a<sub>3</sub> = 9.
- Combination of Linear and Quadratic: The sequence combines linear and quadratic growth.
Example
- a<sub>1</sub> = 1<sup>2</sup> = 1
- a<sub>2</sub> = 2
- a<sub>3</sub> = 3<sup>2</sup> = 9
- a<sub>4</sub> = 4
- a<sub>5</sub> = 5<sup>2</sup> = 25
- a<sub>6</sub> = 6
Interpretation 10: Involving another Sequence
Let a<sub>k</sub> = b<sub>k</sub> * k, where b<sub>k</sub> is the kth Fibonacci number.
Definition
This sequence multiplies each positive integer k with the kth Fibonacci number.
Closed-Form Expression
Since b<sub>k</sub> (the kth Fibonacci number) can be represented with Binet's Formula, we can express a<sub>k</sub> as:
a<sub>k</sub> = k * [((1 + √5)/2)<sup>k</sup> - ((1 - √5)/2)<sup>k</sup>] / √5
Properties
- Monotonically Increasing: Because both k and the Fibonacci numbers are monotonically increasing, this sequence is also strictly increasing.
- Growth Rate: The growth rate is faster than linear, and related to the growth of Fibonacci numbers which is exponential in nature.
Example
- a<sub>1</sub> = 1 * 1 = 1
- a<sub>2</sub> = 2 * 1 = 2
- a<sub>3</sub> = 3 * 2 = 6
- a<sub>4</sub> = 4 * 3 = 12
- a<sub>5</sub> = 5 * 5 = 25
Conclusion
The seemingly simple statement "for each positive integer k let a<sub>k</sub>" can lead to a wide array of interesting sequences, each with its unique properties and characteristics. We explored arithmetic sequences, linear sequences, recurrence relations leading to factorials and triangular numbers, trigonometric sequences, exponential sequences, and even sequences involving prime numbers and piecewise functions. The key takeaway is that the specific definition that follows "for each positive integer k let a<sub>k</sub>" drastically alters the nature of the resulting sequence. Understanding these different types of sequence definitions is crucial for success in many areas of mathematics, computer science, and related fields. The analysis presented showcases how a single, seemingly incomplete prompt can blossom into numerous mathematical investigations, highlighting the richness and interconnectedness of mathematical concepts. Further analysis of such sequences can involve studying their convergence, divergence, asymptotic behavior, and relationships to other mathematical objects.
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